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[UVA][bitmask暴搜] 565 - Pizza Anyone?

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  Pizza Anyone? 

You are responsible for ordering a large pizza for you and your friends. Each of them has told you what he wants on a pizza and what he does not; of course they all understand that since there is only going to be one pizza, no one is likely to have all their requirements satisfied. Can you order a pizza that will satisfy at least one request from all your friends?


The pizza parlor you are calling offers the following pizza toppings; you can include or omit any of them in a pizza:

Input Code Topping
A Anchovies
B Black Olives
C Canadian Bacon
D Diced Garlic
E Extra Cheese
F Fresh Broccoli
G Green Peppers
H Ham
I Italian Sausage
J Jalapeno Peppers
K Kielbasa
L Lean Ground Beef
M Mushrooms
N Nonfat Feta Cheese
O Onions
P Pepperoni

Your friends provide you with a line of text that describes their pizza preferences. For example, the line

+O-H+P;

reveals that someone will accept a pizza with onion, or without ham, or with pepperoni, and the line

-E-I-D+A+J;

indicates that someone else will accept a pizza that omits extra cheese, or Italian sausage, or diced garlic, or that includes anchovies or jalapenos.

Input 

The input consists of a series of pizza constraints.

A pizza constraint is a list of 1 to 12 topping constraint lists each on a line by itself followed by a period on a line by itself.

A topping constraint list is a series of topping requests terminated by a single semicolon.

An topping request is a sign character (+/-) and then an uppercase letter from A to P.

Output 

For each pizza constraint, provide a description of a pizza that satisfies it. A description is the string ``Toppings: " in columns 1 through 10 and then a series of letters, in alphabetical order, listing the toppings on the pizza. So, a pizza with onion, anchovies, fresh broccoli and Canadian bacon would be described by:

Toppings: ACFO

If no combination toppings can be found which satisfies at least one request of every person, your program should print the string

No pizza can satisfy these requests.

on a line by itself starting in column 1.

Sample Input 

+A+B+C+D-E-F-G-H;
-A-B+C+D-E-F+G+H;
-A+B-C+D-E+F-G+H;
.
+A+B+C+D;
+E+F+F+H;
+A+B-G;
+O+J-F;
+H+I+C;
+P;
+O+M+L;
+M-L+P;
.
+A+B+C+D;
+E+F+F+H;
+A+B-G;
+P-O;
+O+J-F;
+H+I+C;
+P;
+O;
+O+M+L;
-O-P;
+M-L+P;
.

Sample Output 

Toppings:
Toppings: CELP
No pizza can satisfy these requests.



Miguel A. Revilla
1998-03-10

窮舉所有可能。

補一下題目意思:每種材料可放或不放,因此 2^16 種,只要符合任一個人至少一項的要求。

//0.464 s

#include <stdio.h>
int main() {
    char s[105];
    int i, j;
    while(1) {
        int person[105][2] = {}, n = 0;
        while(gets(s) && s[0] != '.') {
            for(i = 0; s[i] != ';'; i += 2) {
                if(s[i] == '+')
                    person[n][0] |= 1<<(s[i+1]-'A');
                else
                    person[n][1] |= 1<<(s[i+1]-'A');
            }
            n++;
        }
        if(n == 0)  break;
        int m = 1<<16;
        for(i = 0; i < m; i++) {
            for(j = 0; j < n; j++) {
                if(i&person[j][0])  continue;
                if((m-1-i)&person[j][1])  continue;
                break;
            }
            if(j == n) {
                printf("Toppings: ");
                for(j = 0; j < 16; j++)
                    if((i>>j)&1)
                        putchar(j+'A');
                puts("");
                break;
            }
        }
        if(i == m)
            puts("No pizza can satisfy these requests.");
    }
    return 0;
}

台長: Morris
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