Morris' Blog 我在摸索我存在的意義、生命的意義、內涵及價值。 沒有真正神手般的厲害，套用模式是大部分的情況。 沒那麼厲害的我存在的意義為何，襯托出神的存在？ 有時候不能怪別人不給我機會，我已經開始省思， 為什麼我沒有給別人機會的原因，而是全要靠別人。 有時候我認為我與眾不同，那是因為我做不到很多人能辦到的事情。 我聽不到、玩不起來、說得不夠明瞭、理解得不夠多， 我缺少的語文能力，就是一切一切無能的判定。 為此，我不曉得能做些對別人有幫助的事情。 我知道我自己是個不服輸的性格，但現在我不得不認輸。 我沒有能力，因此我必須認輸。 我到底來這世界作什麼？處處充滿不確定性， 而我總是無法出類拔萃，想當個一般人似乎也回不了頭了。 越強大的挑戰需要越強力的支持，而我的支持是什麼？ 最近嘗試與人談話，但都是失敗的結局，沒人能接受， 不需要言語，不需要溝通，一切所想都表達不出來。

49愛的鼓勵 6訂閱站台

Problem J

Turn the Lights Off

Input: standard input

Output: standard output

Time Limit: 3 seconds

Memory Limit: 32 MB

Since we all rely on mother earth, it's our duty to save her. Therefore, you're now asked to save energy by switching lights off.

A friend of yours has the following problem in his job. There's a grid of size 10x10, where each square has a light bulb and a light switch attached to it. Unfortunately, these lights don't work as they are supposed to. Whenever a switch is pressed, not only its own bulb is switched, but also the ones left, right, above and under it. Of course if a bulb is on the edge of the grid, there are fewer bulbs switched.

When a light switches it means it's now on if it was off before and it's now off if it was on before. Look at the following examples, which show only a small part of the whole grid. They show what happens if the middle switch is pressed. "O" stands for a light that's on, "#" stands for a light that's off.

###      #O#

###  ->  OOO

###      #O#

###      #O#

OOO  ->  ###

###      #O#

Your friend loves to save energy and asks you to write a program that finds out if it is possible to turn all the lights off and if possible then how many times he has to press switches in order to turn all the lights off.

Input

There are several test cases in the input. Each test case is preceded by a single word that gives a name for the test case. After that name there follow 10 lines, each of which contains a 10-letter string consisting of "#" and "O". The end of the input is reached when the name string is "end".

Output

For every test case, print one line that consists of the test case name, a single space character and the minimum number of times your friend has to press a switch. If it is not possible to switch off all the lights or requires more than 100 presses then the case name should be followed by space and then a -1.

Sample Input

all_off

##########

##########

##########

##########

##########

##########

##########

##########

##########

##########

all_on

OOOOOOOOOO

OOOOOOOOOO

OOOOOOOOOO

OOOOOOOOOO

OOOOOOOOOO

OOOOOOOOOO

OOOOOOOOOO

OOOOOOOOOO

OOOOOOOOOO

OOOOOOOOOO

simple

#O########

OOO#######

#O########

####OO####

###O##O###

####OO####

##########

########O#

#######OOO

########O#

end

Sample Output

all_off 0

all_on 44

simple 4

(The Joint Effort Contest, Problem setter: Stefan Pochmann)

#include <stdio.h>
#include <string.h>
char g[15][15];
int ng[15][15], res;
void press(int x, int y) {
    ng[x][y] = !ng[x][y];
    if(x-1 >= 0)    ng[x-1][y] = !ng[x-1][y];
    if(x+1 < 10)    ng[x+1][y] = !ng[x+1][y];
    if(y-1 >= 0)    ng[x][y-1] = !ng[x][y-1];
    if(y+1 < 10)    ng[x][y+1] = !ng[x][y+1];
}
void dfs(int x, int y, int step) {
    if(y == 10)  x++, y = 0;
    if(step >= res) return;
    if(x == 0) {
        dfs(x, y+1, step);
        press(x, y);
        dfs(x, y+1, step+1);
        press(x, y);
    } else if(x < 10) {
        if(ng[x-1][y] == 1) {
            press(x, y);
            dfs(x, y+1, step+1);
            press(x, y);
        } else
            dfs(x, y+1, step);
    } else {
        int i;
        for(i = 0; i < 10; i++)
            if(ng[x-1][i])
                return;
        if(step < res)  res = step;
    }
}
int main() {
    char name[50];
    int i, j;
    while(gets(name)) {
        if(!strcmp(name, "end"))
            break;
        for(i = 0; i < 10; i++)
            gets(g[i]);
        for(i = 0; i < 10; i++) {
            for(j = 0; j < 10; j++) {
                ng[i][j] = g[i][j] == 'O';
            }
        }
        res = 0xffff;
        dfs(0, 0, 0);
        printf("%s %d\n", name, res);
    }
    return 0;
}
/*
all_off
##########
##########
##########
##########
##########
##########
##########
##########
##########
##########
all_on
OOOOOOOOOO
OOOOOOOOOO
OOOOOOOOOO
OOOOOOOOOO
OOOOOOOOOO
OOOOOOOOOO
OOOOOOOOOO
OOOOOOOOOO
OOOOOOOOOO
OOOOOOOOOO
simple
#O########
OOO#######
#O########
####OO####
###O##O###
####OO####
##########
########O#
#######OOO
########O#
*/