9 Puzzle

Alex has a puzzle her father gave her last Christmas. It has nine numbered squares arranged in a 3×3 matrix (three rows and three columns) and it's mechanically designed to allow the following types of movements:

• A horizontal right move shifts one position to the right each of the squares in the corresponding horizontal row (circularly).
• A vertical up move shifts one position upwards each of the squares in the corresponding vertical column (circularly).

Alex's troublemaker little brother Jim snuck last night into his sister's bedroom and somehow tore the puzzle apart and put it back together. However, when Jim assembled the puzzle back, he might have done it in a configuration different from the original configuration of the puzzle.

The next morning, when Alex found her puzzle had been scrambled, she called you to help her to reset her puzzle to its original configuration (shown below) as quickly as possible, so her father won't realize that the puzzle was torn and scrambled. Of course, you should do it using only valid movements, as above described.

Your task is to write a program that, given a configuration, finds a way to set the puzzle to its original configuration spending the minimum possible number of moves to accomplish it, if the given puzzle is solvable. If this is not the case, the program should point it out.

Input 

The problem input consists of several cases, each one defined by three lines that describe a puzzle configuration. That is, lines correspond to a top-down description of the rows of the given configuration, and each line consist of three digits, separated by one blank character.

The end of the input is indicated by a line with a number 0.

Output 

For each puzzle in the input, you must print a line containing S , the minimum number of moves required to set the puzzle to its original configuration, followed by a space and 2*S characters indicating any sequence of S moves that solves the puzzle.

A move is described by two characters: the first one must be H or V (H specifies a horizontal move, and V a vertical move), and the second one must be 1, 2, or 3 to indicate the row or the column to move.

If the puzzle is not solvable, you must output a line with the text ``Not solvable''.

Sample Input 

2 3 1
4 5 6
7 8 9
7 3 9
2 5 1
4 8 6
1 2 3
4 5 6
7 9 8
0

Sample Output 

1 H1
3 V1V3H1
Not solvable

---

盡力壓秒速了，還是不夠快。

#include <stdio.h>
#include <map>
#include <queue>
#include <iostream>
#define hash_r 100003
using namespace std;
struct edge {
    int to;
    char v1, v2;
};
map<int, edge> R[hash_r];
void insert(int state, edge& s) {
    R[state%hash_r][state] = s;
}
int find(int state) {
    return R[state%hash_r].find(state) != R[state%hash_r].end();
}
void init_bfs() {
    edge E;
    E.to = -1;
    insert(123456789, E);
    int i, j, k, state, tn, tmp;
    int board[3][3];
    char v;
    queue<int> Q;
    Q.push(123456789);
    while(!Q.empty()) {
        state = tn = Q.front();
        Q.pop();
        for(i = 2; i >= 0; i--) {
            for(j = 2; j >= 0; j--) {
                board[i][j] = tn%10;
                tn /= 10;
            }
        }
        /*for(i = 0; i < 3; i++, puts(""))
            for(j = 0; j < 3; j++)
                printf("%d", board[i][j]);
        printf("--");
        getchar();*/
        for(i = 0; i < 3; i++) {
            tn = board[i][0];
            for(j = 1; j < 3; j++)
                board[i][j-1] = board[i][j];
            board[i][2] = tn;
           // printf("H%d\n", tn);
            tmp = 0;
            for(j = 0; j < 3; j++)
                for(k = 0; k < 3; k++)
                    tmp = tmp*10 + board[j][k];
            if(!find(tmp)) {
                E.to = state;
                E.v1 = 'H', E.v2 = i+1+'0';
                insert(tmp, E);
                Q.push(tmp);
            }
            tn = board[i][2];
            for(j = 1; j >= 0; j--)
                board[i][j+1] = board[i][j];
            board[i][0] = tn;
        }
        for(i = 0; i < 3; i++) {
            tn = board[2][i];
            for(j = 1; j >= 0; j--)
                board[j+1][i] = board[j][i];
            board[0][i] = tn;
           // printf("V%d\n", tn);
            tmp = 0;
            for(j = 0; j < 3; j++)
                for(k = 0; k < 3; k++)
                    tmp = tmp*10 + board[j][k];
            if(!find(tmp)) {
                E.to = state;
                E.v1 = 'V', E.v2 = i+1+'0';
                insert(tmp, E);
                Q.push(tmp);
            }
            tn = board[0][i];
            for(j = 1; j < 3; j++)
                board[j-1][i] = board[j][i];
            board[2][i] = tn;
        }
    }
}
char way[250];
int len;
void back(int state) {
    if(state == 123456789)  return;
    edge E = R[state%hash_r][state];
    way[len++] = E.v1;
    way[len++] = E.v2;
    back(E.to);
}
int main() {
    init_bfs();
    while(1) {
        int x, i, state = 0;
        for(i = 0; i < 9; i++) {
            if(scanf("%d", &x) != 1)
                return 0;
            state = state *10 + x;
        }
        if(!find(state))
            puts("Not solvable");
        else {
            len = 0, back(state);
            way[len] = '\0';
            if(len)
                printf("%d %s\n", len/2, way);
            else
                puts("0");
        }
    }
    return 0;
}