Morris' Blog 我在摸索我存在的意義、生命的意義、內涵及價值。 沒有真正神手般的厲害，套用模式是大部分的情況。 沒那麼厲害的我存在的意義為何，襯托出神的存在？ 有時候不能怪別人不給我機會，我已經開始省思， 為什麼我沒有給別人機會的原因，而是全要靠別人。 有時候我認為我與眾不同，那是因為我做不到很多人能辦到的事情。 我聽不到、玩不起來、說得不夠明瞭、理解得不夠多， 我缺少的語文能力，就是一切一切無能的判定。 為此，我不曉得能做些對別人有幫助的事情。 我知道我自己是個不服輸的性格，但現在我不得不認輸。 我沒有能力，因此我必須認輸。 我到底來這世界作什麼？處處充滿不確定性， 而我總是無法出類拔萃，想當個一般人似乎也回不了頭了。 越強大的挑戰需要越強力的支持，而我的支持是什麼？ 最近嘗試與人談話，但都是失敗的結局，沒人能接受， 不需要言語，不需要溝通，一切所想都表達不出來。

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Background

Typical slide presentation programs such as OpenOffice Impress, Kpresenter or PowerPoint are able to fit the text that the user writes into slides by changing the size of the font used for the text, so that the entire text can fit into the slide.

Those programs start using a font with a typical font size (measured in points). When the text typed by the user does not fit into the slide, they try to use a smaller font (less size in points) to fit the text into the slide.

Thus, presentation programs must apply an algorithm to calculate the bigger font size that allows the typed text to fit into the slide.

The Problem

You have to write a program to solve this problem. Given a set of paragraphs that have to be written into a slide, you have to calculate the maximum font size in points that allows all the text to fit into the slide.

There are some additional rules to consider: all characters (including spaces) have the same size in points, PxP, where P is the selected font size in points. Font sizes can vary from 8 to 28 points. If a paragraph cannot be fit into one line, wrapping can occur, but only at word boundaries (i.e., after one space). Thus, a paragraph can use several horizontal lines.

The Input

The input begins with a line with an integer N indicating the number of slides. Each slide starts with a number M, indicating the number of paragraphs of this slide. Then, M lines of text follow, one for each paragraph. And finally a line with two integers (X and Y), indicating the size of the slide in points. There will not be more than one space between words, and neither empty paragraphs. You can also assume that there are not spaces at the beginning or at the end of a paragraph.

The Output

The output will consist of N lines (one for each slide). Each line will be either "No solution" (if the text cannot be fit with any point size between 8 and 28), or P, the maximum size of the font in points that allows the slide to fit the paragraphs.

Sample Input

3
3
En un lugar de la mancha
de cuyo nombre no quiero acordarme
no ha mucho que vivia...
375 35
1
LE LO
40 40
2
I love this hyper-mega-cosmic-contest.
The winner.
100 80

Sample Output

11
20
No solution

---

犯了一個很蠢的錯誤在於, 忘記空白(space ' ')也要同時變成 P*P

 
#include <iostream>
#include <sstream>
using namespace std;

int main() {
    int t, n, X, Y;
    cin >> t;
    while(t--) {
        cin >> n;
        cin.ignore(100, '\n');
        string p[100][100], in;
        int pw[100] = {};
        for(int i = 0; i < n; i++) {
            getline(cin, in);
            stringstream sin;
            sin << in;
            while(sin >> p[i][pw[i]])
                pw[i]++;
        }
        cin >> Y >> X;
        int font, i, j;
        for(font = 28; font >= 8; font--) {
            if(font*n > X)  continue;
            int x = 0, y = 0;
            int first;
            for(i = 0; i < n; i++) {
                x += font, y = 0;
                first = 0;
                for(j = 0; j < pw[i]; j++) {
                    if(y+font*(p[i][j].length()+first) > Y) {
                        x += font, y = font*p[i][j].length();
                    } else {
                        y += font*(p[i][j].length()+first);
                    }
                    if(y > Y || x > X) {
                        x = X+1;
                        break;
                    }
                    first = 1; // space
                }
            }
            if(x <= X) {
                cout << font << endl;
                break;
            }
        }
        if(font == 7)
            cout << "No solution" << endl;
    }
    return 0;
}