Morris' Blog 我在摸索我存在的意義、生命的意義、內涵及價值。 沒有真正神手般的厲害，套用模式是大部分的情況。 沒那麼厲害的我存在的意義為何，襯托出神的存在？ 有時候不能怪別人不給我機會，我已經開始省思， 為什麼我沒有給別人機會的原因，而是全要靠別人。 有時候我認為我與眾不同，那是因為我做不到很多人能辦到的事情。 我聽不到、玩不起來、說得不夠明瞭、理解得不夠多， 我缺少的語文能力，就是一切一切無能的判定。 為此，我不曉得能做些對別人有幫助的事情。 我知道我自己是個不服輸的性格，但現在我不得不認輸。 我沒有能力，因此我必須認輸。 我到底來這世界作什麼？處處充滿不確定性， 而我總是無法出類拔萃，想當個一般人似乎也回不了頭了。 越強大的挑戰需要越強力的支持，而我的支持是什麼？ 最近嘗試與人談話，但都是失敗的結局，沒人能接受， 不需要言語，不需要溝通，一切所想都表達不出來。

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Can You Solve It?
Input: standard input
Output: standard output
Time Limit: 1 second

First take a look at the following picture. In this picture, each circle has a coordinate according to Cartesian Coordinate System. You can move from one circle to another following the path denoted by forward arrow symbols. To go from a source circle to a destination circle, total number of step(s) needed = ( number of intermediate circles you pass + 1 ). For example, to go from ( 0 , 3 ) to ( 3 , 0 ) you have to pass two intermediate circles ( 1 , 2 ) and ( 2 , 1 ). So, in this case, total number of steps needed is 2 + 1 = 3. In this problem, you are to calculate number of step(s) needed for a given source circle and a destination circle. You can assume that, it is not possible to go back using the reverse direction of the arrows.

The first line in the input is the number of test cases n ( 0 < n <= 500 ) to handle. Following there are n lines each containing four integers ( 0 <= each integer <=100000 ) the first pair of which represents the coordinates of the source circle and the other represents that of the destination circle. The coordinates are listed in a form ( x , y ).

Output

For each pair of integers your program should output the case number first and then the number of step(s) to reach the destination from the source. You may assume that it is always possible to reach the destination circle from the source circle.

Sample Input

3
0 0 0 1
0 0 1 0
0 0 0 2

Sample Output

Case 1: 1
Case 2: 2
Case 3: 3