Morris' Blog 我在摸索我存在的意義、生命的意義、內涵及價值。 沒有真正神手般的厲害，套用模式是大部分的情況。 沒那麼厲害的我存在的意義為何，襯托出神的存在？ 有時候不能怪別人不給我機會，我已經開始省思， 為什麼我沒有給別人機會的原因，而是全要靠別人。 有時候我認為我與眾不同，那是因為我做不到很多人能辦到的事情。 我聽不到、玩不起來、說得不夠明瞭、理解得不夠多， 我缺少的語文能力，就是一切一切無能的判定。 為此，我不曉得能做些對別人有幫助的事情。 我知道我自己是個不服輸的性格，但現在我不得不認輸。 我沒有能力，因此我必須認輸。 我到底來這世界作什麼？處處充滿不確定性， 而我總是無法出類拔萃，想當個一般人似乎也回不了頭了。 越強大的挑戰需要越強力的支持，而我的支持是什麼？ 最近嘗試與人談話，但都是失敗的結局，沒人能接受， 不需要言語，不需要溝通，一切所想都表達不出來。

49愛的鼓勵 6訂閱站台

C	Code Creator

 

With increased popularity of programming competitions, there are so many online judges where contestants can practice. Usually, most of these sites allow users to submit solutions to problems and if they are accepted, the users total number of solved is increased. To increase competition among users, these sites maintain a ranking of users based on the total number of solves. Unfortunately, this at times has introduced unhealthy competition among some users. A lot of the problems at these sites are collected from external sites, and the online judge uses data file directly from these external sites. This means, for certain problem, one is only required to submit the output file to get a problem accepted, without solving the problem at all. Just out of curiosity, you try to investigate how many of these problems are actually using judge data from the external site. To accelerate your investigation, you want to automate the process of creating codes that will submit judge data only. In this problem, you are required to make such a code generator.

Input

Each case of input starts with a positive integer N<100. N lines follow each containing at least 1 and at most 100 characters. The Input characters will consist of alphanumeric, spaces, backslash and quotation only. The last case is followed by a value of 0 for N.

Output

Each case of output will start with a line containing the case number in the format Case x: where x is the case number. The next few lines will be a C code which when compiled and run will generate the input given for that case. Since there are so many ways to write a program that will generate the same output, for this problem we will restrict ourselves to the following format.

#include<string.h>
#include<stdio.h>
int main()
{
<case specific lines>
printf(“\n”);
return 0;
}

 

<case specific lines> will contain the same number of lines as N for that case, each formatted as: printf(“<line>\n”); where <line> is the input value entered for that corresponding line. Note that, the two characters “ and \ must be escaped by a \ in order to be displayed by printf . The sample input/output will clarify further.

In case you are curious, why there is a printf(“\n”); before the return 0; , it’s there to get this code presentation error so that it’s not counted as accepted. You don’t want to increase your number that way, do you?

Sample Input

2

“I like to solve”
I do not like to code
1
yeah accepted
0

Sample Output

Case 1:
#include<string.h>
#include<stdio.h>
int main()
{
printf(“\”I like to solve\”\n”);
printf(“I do not like to code\n”);
printf(“\n”);
return 0;
}
Case 2:
#include<string.h>
#include<stdio.h>
int main()
{
printf(“yeah accepted\n”);
printf(“\n”);
return 0;
}

---

只需要注意 '\\' 跟 '\"' 即可

#include<stdio.h>
int main() {
    int n, Case = 0, i, j;
    char str[1002];
    while(scanf("%d", &n) == 1 && n) {
        getchar();
        printf("Case %d:\n", ++Case);
        puts("#include<string.h>\n#include<stdio.h>\nint main()\n{");
        while(n--) {
            gets(str);
            printf("printf(\"");
            for(i = 0; str[i]; i++) {
                if(str[i] == '\\' || str[i] == '\"')
                    printf("\\");
                printf("%c", str[i]);
            }
            printf("\\n\");\n");
        }
        puts("printf(\"\\n\");\nreturn 0;\n}");
    }
    return 0;
}